Jedno z mala dobrych vyuziti AI, kedze zbezna kontrola vzorcov je OK a ak sa Gemini ukleplo, tak mi je to jedno:
Calculate power loss in W for a three phase cable at current 16A per phase with cable length 20m.
Give results in table for wire cross sections of 4mm2, 6mm2, 10mm2 and 16mm2.
Of course! Here is the calculated power loss for a three-phase cable with a current of 16A per phase and a length of 20m, for various wire cross-sections.
Power Loss Calculation
The power loss was calculated using the formula:
P=3×I
2
×R
Where:
P is the power loss in Watts (W).
I is the current per phase in Amperes (A).
R is the resistance of a single conductor in Ohms (Ω).
The resistance of the conductor was calculated using the formula:
R=
A
ρ×L
Where:
ρ (rho) is the resistivity of copper, which is approximately 1.68×10
−8
Ω⋅m.
L is the length of the cable in meters (m).
A is the cross-sectional area of the wire in square meters (m
2
).
Results
Here are the calculated power loss values for each specified wire cross-section:
Cross-section (mm²) Power Loss (W)
4 64.51
6 43.01
10 25.80
16 16.13
Export to Sheets
As you can see from the table, as the wire's cross-sectional area increases, the resistance of the cable decreases, leading to a lower power loss.
Tak si tie Watty vynasobte poctom nabijacich hodin za rok a cenou elektriny a mate vystarane.
Realisticky, casom si kupite druhe alebo nove auto a extra vykon sa vam vzdy zide, dajte tam rovno 5x16.
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